Let C be the centre of the circle x^2+y^2-x+2y= 11 4 and P be a point on the circle. A line passes through the point C, makes an angle of π 4 with…
JEE Main 2022 — Mathematics Coordinate Geometry
2022mcqmedium
Let C be the centre of the circle x2+y2−x+2y=411 and P be a point on the circle. A line passes through the point C, makes an angle of 4π with the line CP and intersects the circle at the points Q and R. Then the area of the triangle PQR (in unit2) is
Official previous-year question
Held on 28 Jul 2022 · Verified 6 Jul 2026.
Options
A
2
B
22
C
8sin(8π)
D
8cos(8π)
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Solution
Given,
x2+y2−x+2y=411
On rearranging terms we get,
⇒(x−21)2+(y+1)2=(2)2
Now given in ΔPQR, ∠PCR=4π so ∠PQR=2221 by circle property, radius is 2 so RC=QC=2
Now, PR=QRsin2221=4sin8π
And PQ=QRcos2221=4cos2221
Now area of ΔPQR=21PR×PQ
=21(4sin8π)(4cos8π)
=4×(2sin8πcos8π)
=4sin4π=24=22
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