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Let a triangle ABC be inscribed in the circle x^2-√2(x+y)+y^2=0 such that angle BAC= π 2. If the length of side AB is √2, then the area of the…

JEE Main 2022 — Mathematics Coordinate Geometry

2022mcqmedium

Let a triangle ABCABCABC be inscribed in the circle x2−2(x+y)+y2=0{x}^{2}-\sqrt{2}(x+y)+{y}^{2}=0x2−2​(x+y)+y2=0 such that ∠BAC=π2\angle BAC=\frac{\pi }{2}∠BAC=2π​. If the length of side ABABAB is 2\sqrt{2}2​, then the area of the △ABC\triangle ABC△ABC is equal to:

Official previous-year question

Held on 29 Jun 2022 · Verified 6 Jul 2026.

Options

  1. A

    111

  2. B

    (6+3)2\frac{(\sqrt{6}+\sqrt{3})}{2}2(6​+3​)​

  3. C

    (3+3)2\frac{(\sqrt{3}+\sqrt{3})}{2}2(3​+3​)​

  4. D

    (6+23)4\frac{(\sqrt{6}+2\sqrt{3})}{4}4(6​+23​)​

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