Given,
circle x2−2(x+y)+y2=0
With centre (21,21) and radius 1.
Since ∠BAC=2π, so BC will act as diameter,
BC=diameter=2 (given)
So, AC=BC2−AB2=2 and AB=2
Now, △ABC=21AB⋅AC=1
JEE Main 2022 — Mathematics Coordinate Geometry
Let a triangle ABC be inscribed in the circle x2−2(x+y)+y2=0 such that ∠BAC=2π. If the length of side AB is 2, then the area of the △ABC is equal to:
Held on 29 Jun 2022 · Verified 6 Jul 2026.
1
2(6+3)
2(3+3)
4(6+23)
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