Given, the equation of circle is x2+y2−2x−6y+6=0
So, the centre of the circle is (1,3) and the radius is 12+32−6=2
Assume, the coordinate of point B is (−1,k) and the coordinate of point A is (h,1).
So, (h+1)2=2⇒h=1 and (k−1)2=2⇒k=3
So, the coordinate of B is (−1,3) and the coordinate of A is (1,1).

From the diagram, area of ΔABD=21×2×4
=4 sq. units