Given

Slope of OA=2−h5−2(h−4)=m1Slope of the given tangent equation=m2=2
⇒(2−h5−2(h−4))(2)=−1
⇒h=8
Center=(8,2)
Radius=(8−2)2+(2−5)2=35
JEE Main 2021 — Mathematics Coordinate Geometry
The line 2x−y+1=0 is a tangent to the circle at the point (2,5) and the centre of the circle lies on x−2y=4. Then, the radius of the circle is:
Held on 17 Mar 2021 · Verified 6 Jul 2026.
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