
Mid point M=(t,3)
mAB=t−3
Perpendicular bisector of AB is
y−3=3t(x−t)
So, C=(0,3−3t2)
Let P be (h,k)
h=2t;k=3−6t2
⇒k=3−64h2
⇒2x2+3y−9=0
JEE Main 2021 — Mathematics Coordinate Geometry
Let A be a fixed point (0,6) and B be a moving point (2t,0). Let M be the mid-point of AB and the perpendicular bisector of AB meets the y−axis at C. The locus of the mid-point P of MC is
Held on 27 Aug 2021 · Verified 6 Jul 2026.
3x2+2y−6=0
2x2−3y+9=0
3x2−2y−6=0
2x2+3y−9=0
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