Δ=21∣01x’2−1y’111∣
⇒−2(1−x’)+(y’+x’)=±10
⇒−2+2x’+y’+x’=±10
⇒3x’+y’=12 Or 3x’+y’=−8...(i)
(x’,y’) lies on the line 3x+y−4λ=0,
So, 3x’+y’−4λ=0...(ii)
Solving (i) and (ii), we get,
λ=3,−2
JEE Main 2020 — Mathematics Coordinate Geometry
Let two points be A(1,−1) and B(0,2). If a point P(x’,y’) be such that the area of ΔPAB=5 sq. units and it lies on the line 3x+y−4λ=0, then a value of λ is
Held on 8 Jan 2020 · Verified 6 Jul 2026.
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