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Let the tangents drawn from the origin to the circle, x^2+y^2-8x-4y+16=0 touch it at the points A and B . Then (AB)^2 is equal to

JEE Main 2020 — Mathematics Coordinate Geometry

2020mcqmedium

Let the tangents drawn from the origin to the circle, x2+y2−8x−4y+16=0{x}^{2}+{y}^{2}-8x-4y+16=0x2+y2−8x−4y+16=0 touch it at the points AAA and BBB . Then (AB)2{(AB)}^{2}(AB)2 is equal to

Official previous-year question

Held on 7 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    525\frac{52}{5}552​

  2. B

    565\frac{56}{5}556​

  3. C

    645\frac{64}{5}564​

  4. D

    325\frac{32}{5}532​

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