Skip to main content

A triangle ABC lying in the first quadrant has two vertices as A(1,2) and B(3,1). Ifangle BAC=90^o,and ar(Δ ABC)=5√5 sq. units, then the abscissa of…

JEE Main 2020 — Mathematics Coordinate Geometry

2020mcqmedium

A triangle ABCABCABC lying in the first quadrant has two vertices as A(1,2)A(1,2)A(1,2) and B(3,1)B(3,1)B(3,1). If∠BAC=90o,\angle BAC={90}^{o},∠BAC=90o,and ar(ΔABC)=55ar(\Delta \mathrm{ABC})=5\sqrt{5}ar(ΔABC)=55​ sq. units, then the abscissa of the vertex CCC is :

Official previous-year question

Held on 4 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    1+51+\sqrt{5}1+5​

  2. B

    1+251+2\sqrt{5}1+25​

  3. C

    2+52+\sqrt{5}2+5​

  4. D

    25−12\sqrt{5}-125​−1

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics