Solving the equations of the given parabola and the line, we get,
(2y−42)2=4y⇒y2−10y+16=0
⇒∣y1−y2∣=(y1+y2)2−4y1y2=100−64=6
⇒ Length of the chord =AB=(x1−x2)2+(y1−y2)2=2(y1−y2)2+(y1−y2)2=3∣y1−y2∣
=63 units
JEE Main 2019 — Mathematics Coordinate Geometry
The length of the chord of the parabola x2=4y having equation x−2y+42=0 is
Held on 10 Jan 2019 · Verified 6 Jul 2026.
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