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Let the equations of two sides of a triangle be 3x-2y+6=0 and 4x+5y-20=0. If the orthocenter of this triangle is at (1, 1) then the equation of it's…

JEE Main 2019 — Mathematics Coordinate Geometry

2019mcqhard

Let the equations of two sides of a triangle be 3x−2y+6=03x-2y+6=03x−2y+6=0 and 4x+5y−20=0.4x+5y-20=0.4x+5y−20=0. If the orthocenter of this triangle is at (1,1)(1, 1)(1,1) then the equation of it's third side is:

Official previous-year question

Held on 9 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    122y+26x+1675=0122y+26x+1675=0122y+26x+1675=0

  2. B

    26x−122y−1675=026x-122y-1675=026x−122y−1675=0

  3. C

    26x+61y+1675=026x+61y+1675=026x+61y+1675=0

  4. D

    122y−26x−1675=0122y-26x-1675=0122y−26x−1675=0

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