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Let 0<θ < π 2. If the eccentricity of the hyperbola x^2 cos^2⁡θ - y^2 sin^2⁡θ =1 is greater than 2, then the length of its latus rectum lies in the…

JEE Main 2019 — Mathematics Coordinate Geometry

2019mcqmedium

Let 0<θ<π2.0<\theta <\frac{\pi }{2}.0<θ<2π​. If the eccentricity of the hyperbola x2cos2⁡θ−y2sin2⁡θ=1\frac{{x}^{2}}{{\mathrm{cos}}^{2}⁡\theta }-\frac{{y}^{2}}{{\mathrm{sin}}^{2}⁡\theta }=1cos2⁡θx2​−sin2⁡θy2​=1 is greater than 2,2,2, then the length of its latus rectum lies in the interval:

Official previous-year question

Held on 9 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    (3,∞)(3, \infty )(3,∞)

  2. B

    (1,32](1, \frac{3}{2}](1,23​]

  3. C

    (2,3](2, 3](2,3]

  4. D

    (32,2](\frac{3}{2}, 2](23​,2]

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