Since the vertex of given triangle is O (origin) and other two vertices A and B lies on the coordinate axes, hence triangle must be a right-angled triangle.
Area =21x.y(x,y∈I)
As per given condition
21x.y=50⇒x.y=100
Possible ordered pairs of (x,y) when Δ formed in 1st quadrant are 9 i. e. (1,100),(2,50),(4,25),(5,20),(10,10),(25,4),(50,2),(100,1)
Δ can be formed in any of the quadrants, hence total number of cases 9×4=36.
