
Given, OA+PO+PA=4⇒PO+PA=3
⇒Locus of P is ellipse with foci at O & A and major
axis (2b)=3
Distance between foci =2be=1⇒e=31
⇒Minor axis 2a=2b1−e2=3.322=22
⇒ Equation of Locus of P is :
8x2+9(y−21)2=41
By simplifying the above equation, we get
9x2+8y2−8y=16