A triangle has a vertex at (1,2) and the mid points of the two sides through it are (−1,1) and (2,3) . Then the centroid of this triangle is:
Held on 12 Apr 2019 · Verified 6 Jul 2026.
(31,1)
(1,37)
(31,2)
(31,35)
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Let the image of parabola $x^{2}=4 y$, in the line $x-y=1$ be $(y+a)^{2}=b(x-c)$, $a, b, c \in \mathrm{~N}$. Then $a+b+c$ is equal to
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