The equation of circle is, x2+y2−6x+8y−103=0 ⇒(x−3)2+(y+4)2=(82)2 C(3,−4),r=82 ⇒ Length of side of square =2r=16 
⇒P(−5,4),Q(−5,−12) R(11,−12),S(11,4) ⇒ Required distance =OP =(−5−0)2+(−4−0)2=25+16=41
JEE Main 2019 — Mathematics Coordinate Geometry
A square is inscribed in the circle x2+y2−6x+8y−103=0 with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is:
Held on 11 Jan 2019 · Verified 6 Jul 2026.
6
137
41
13
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