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A square is inscribed in the circle x^2+y^2-6 x+8 y-103=0 with its sides parallel to the coordinate axes. Then the distance of the vertex of this…

JEE Main 2019 — Mathematics Coordinate Geometry

2019mcqmedium

A square is inscribed in the circle x2+y2−6x+8y−103=0x^{2}+y^{2}-6 x+8 y-103=0x2+y2−6x+8y−103=0 with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is:

Official previous-year question

Held on 11 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    6

  2. B

    137\sqrt{137}137​

  3. C

    41\sqrt{41}41​

  4. D

    13

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