
Since circle touches the x-axis at (3,0), hence centre can be taken as (3,α) and radius =∣α∣
Since y-intercept is 8, by applying Pythagorean theorem
32+42=α2⇒α=5,−5
Hence two circles are possible
(x−3)2+(y−5)2=25 and (x−3)2+(y+5)2=25.
Clearly (3,10) satisfies the given equation of circle.