Skip to main content

If β is one of the angles between the normals to the ellipse x^2+3y^2=9 at the points (3 cosθ ,√3 sinθ ) and (-3 sinθ ,√3 cosθ );θ ∈ (0, π 2); then 2…

JEE Main 2018 — Mathematics Coordinate Geometry

2018mcqmedium

If β\betaβ is one of the angles between the normals to the ellipse x2+3y2=9{x}^{2}+3{y}^{2}=9x2+3y2=9 at the points (3cosθ,3sinθ)(3\mathrm{cos}\theta ,\sqrt{3}\mathrm{sin}\theta )(3cosθ,3​sinθ) and (−3sinθ,3cosθ);θ∈(0,π2)(-3\mathrm{sin}\theta ,\sqrt{3}\mathrm{cos}\theta );\theta \in (0,\frac{\pi }{2})(−3sinθ,3​cosθ);θ∈(0,2π​); then 2cotβsin2θ\frac{2\mathrm{cot}\beta }{\mathrm{sin}2\theta }sin2θ2cotβ​ is equal to :

Official previous-year question

Held on 15 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    13\frac{1}{\sqrt{3}}3​1​

  2. B

    34\frac{\sqrt{3}}{4}43​​

  3. C

    23\frac{2}{\sqrt{3}}3​2​

  4. D

    2\sqrt{2}2​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics