Equation of the line passing through the points (2,3) and (4,5) is y−3=(4−25−3)x−2⇒x−y+1=0 Equation of the perpendicular line passing through the midpoint (3,4) is x+y−7=0 Lines (1) and (2) intersect at the center of the circle. So, the center of the circle is (3,4) Therefore, the radius is (x2−x1)2+(y2−y1)2=(2−3)2+(3−4)2=2 units.