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Let a and b respectively be the semi-transverse and semi-conjugate axes of a standard hyperbola whose eccentricity satisfies the equation…

JEE Main 2016 — Mathematics Coordinate Geometry

2016mcqeasy

Let aaa and bbb respectively be the semi-transverse and semi-conjugate axes of a standard hyperbola whose eccentricity satisfies the equation 9e2−18e+5=09{e}^{2}-18e+5=09e2−18e+5=0. If S(5,0)S(5, 0)S(5,0) is a focus and 5x=95x=95x=9 is the corresponding directrix of this hyperbola, then a2−b2{a}^{2}-{b}^{2}a2−b2 is equal to

Official previous-year question

Held on 9 Apr 2016 · Verified 6 Jul 2026.

Options

  1. A

    −7-7−7

  2. B

    −5-5−5

  3. C

    555

  4. D

    777

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