If the incentre of an equilateral triangle is (1,1) and the equation of its one side is 3x+4y+3=0, then the equation of the circumcircle of this triangle is:
Held on 11 Apr 2015 · Verified 6 Jul 2026.
x2+y2−2x−2y−2=0
x2+y2−2x−2y+2=0
x2+y2−2x−2y−7=0
x2+y2−2x−2y−14=0
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Let the image of parabola $x^{2}=4 y$, in the line $x-y=1$ be $(y+a)^{2}=b(x-c)$, $a, b, c \in \mathrm{~N}$. Then $a+b+c$ is equal to
The distance between the points (3, 4) and (6, 8) is:
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Let a point $A$ lie between the parallel lines $L_{1}$ and $L_{2}$ such that its distances from $L_{1}$ and $L_{2}$ are 6 and 3 units, respectively. Then the area (in sq. units) of the equilateral triangle $A B C$, where the points $B$ and C lie on the lines $\mathrm{L}_{1}$ and $\mathrm{L}_{2}$, respectively, is :
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