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If the incentre of an equilateral triangle is (1,1) and the equation of its one side is 3x+4y+3=0, then the equation of the circumcircle of this…

JEE Main 2015 — Mathematics Coordinate Geometry

2015mcqmedium

If the incentre of an equilateral triangle is (1,1)(1,1)(1,1) and the equation of its one side is 3x+4y+3=03x+4y+3=03x+4y+3=0, then the equation of the circumcircle of this triangle is:

Official previous-year question

Held on 11 Apr 2015 · Verified 6 Jul 2026.

Options

  1. A

    x2+y2−2x−2y−2=0{x}^{2}+{y}^{2}-2x-2y-2=0x2+y2−2x−2y−2=0

  2. B

    x2+y2−2x−2y+2=0{x}^{2}+{y}^{2}-2x-2y+2=0x2+y2−2x−2y+2=0

  3. C

    x2+y2−2x−2y−7=0{x}^{2}+{y}^{2}-2x-2y-7=0x2+y2−2x−2y−7=0

  4. D

    x2+y2−2x−2y−14=0{x}^{2}+{y}^{2}-2x-2y-14=0x2+y2−2x−2y−14=0

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