x+2ay+a=0x+3by+b=0x+4ay+a=0 Subtracting equation (3) from (1) −2ay=0ay=0⇒y=0 Putting value of y in equation (1), we get x+0+a=0x=−a Putting value of x and y in equation (2), we get −a+b=0a=b Thus, (a,b) lies on a straight line
JEE Main 2014 — Mathematics Coordinate Geometry
If the three distinct lines x+2ay+a=0,x+3by +b=0 and x+4ay+a=0 are concurrent, then the point (a,b) lies on a :
Held on 12 Apr 2014 · Verified 6 Jul 2026.
circle
hyperbola
straight line
parabola
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