Given sin−1x>cos−1x where x∈(0,1) ⇒sin−1x>2π−sin−1x⇒2sin−1x>2π⇒sin−1x>4π⇒x>sin4π⇒x>21 Maximum value of sin−1x is 2π So, maximum value of x is 1 . So, x∈(21,1)
Let x ∈(0,1). The set of all x such that sin ^-1 x>cos ^-1 x, is the interval:
JEE Main 2013 — Mathematics Coordinate Geometry
Let x∈(0,1). The set of all x such that sin−1x>cos−1x, is the interval:
Held on 25 Apr 2013 · Verified 6 Jul 2026.
Options
- A
(21,21)
- B
(21,1)
- C
(0,1)
- D
(0,23)
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