Mid-point of P(2,3) and Q(4,5)=(3,4) Slope of PQ = 1 Slope of the line L=−1 Mid-point (3,4) lies on the line L. Equation of line L, y−4=−1(x−3)⇒x+y−7=0 Let image of point R(0,0) be S(x1,y1) Mid-point of RS=(2x1,2y1) Mid-point (2x1,2y1) lies on the line (i) x1+y1=14 Slope of RS =x1y1 Since RS⊥ line L x1y1×(−1)=−1x1=y1 From (ii) and (iii), x1=y1=7 Hence the image of R=(7,7)