Given line 3x+4y=12 can be rewritten as 123x+124y=1⇒4x+3y=1⇒x-intercept =4 and y-intercept =3 Let the required line be L:ax+by=1 where a=x-intercept and b=y-intercept According to the question a=4×2=8 and b=3/2 ∴ Required line is 8x+32y=1 ⇒3x+16y=24 ⇒y=16−3x+1624 Hence, required slope =16−3.