The point of intersection of the lines (a^3+3 ) x+a y+a-3=0 and (a^5+2 ) x+(a+2) y+2 a+3=0 (a real) lies on the y-axis for
JEE Main 2012 — Mathematics Coordinate Geometry
2012mcqhard
The point of intersection of the lines (a3+3)x+ay+a−3=0 and (a5+2)x+(a+2)y+2a+3=0 (a real) lies on the y-axis for
Official previous-year question
Held on 7 May 2012 · Verified 6 Jul 2026.
Options
A
no value of a
B
more than two values of a
C
exactly one value of a
D
exactly two values of a
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Solution
Given equation of lines are (a3+3)x+ay+a−3=0 and (a5+2)x+(a+2)y+2a+3=0 (a real) Since point of intersection of lines lies on y-axis. ∴ Put x=0 in each equation, we get ay+a−3=0 and (a+2)y+2a+3=0 On solving these we get (a+2)(a−3)−a(2a+3)=0⇒a2−a−6−2a2−3a=0⇒−a2−4a−6=0⇒a2+4a+6=0⇒a=2−4±16−24=2−4±−8( not real) This shows that the point of intersection of the lines lies on the y-axis for no value of ' a '.
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