a+b2(a+b)2−ab=1⇒(a+b)2=4(a2+b2+ab)⇒3a2+3b2+2ab=0.
If the pair of lines a x^2+2(a+b) x y+b y^2=0 lie along diameters of a circle and divide the circle into four sectors such that the area of one of…
JEE Main 2005 — Mathematics Coordinate Geometry
If the pair of lines ax2+2(a+b)xy+by2=0 lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then
Held on 30 Apr 2005 · Verified 6 Jul 2026.
Options
- A
3a2−10ab+3b2=0
- B
3a2−2ab+3b2=0
- C
3a2+10ab+3b2=0
- D
3a2+2ab+3b2=0
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