Let the centre be (α,β) ∵ It cut the circle x2+y2=p2 orthogonally 2(−α)×0+2(−β)×0=c1−p2 c1=p2 Let equation of circle is x2+y2−2αx−2βy+p2=0 It pass through (a,b)⇒a2+b2−2αa−2βb+p2=0 Locus ∴2ax+2by−(a2+b2+p2)=0
If a circle passes through the point (a, b) and cuts the circle x^2+y^2=p^2 orthogonally, then the equation of the locus of its centre is
JEE Main 2005 — Mathematics Coordinate Geometry
If a circle passes through the point (a,b) and cuts the circle x2+y2=p2 orthogonally, then the equation of the locus of its centre is
Held on 30 Apr 2005 · Verified 6 Jul 2026.
Options
- A
x2+y2−3ax−4by+(a2+b2−p2)=0
- B
2ax+2by−(a2−b2+p2)=0
- C
x2+y2−2ax−3by+(a2−b2−p2)=0
- D
2ax+2by−(a2+b2+p2)=0
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