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If a circle passes through the point (a, b) and cuts the circle x^2+y^2=p^2 orthogonally, then the equation of the locus of its centre is

JEE Main 2005 — Mathematics Coordinate Geometry

2005mcqhard

If a circle passes through the point (a,b)(a, b)(a,b) and cuts the circle x2+y2=p2x^2+y^2=p^2x2+y2=p2 orthogonally, then the equation of the locus of its centre is

Official previous-year question

Held on 30 Apr 2005 · Verified 6 Jul 2026.

Options

  1. A

    x2+y2−3ax−4by+(a2+b2−p2)=0x^2+y^2-3 a x-4 b y+\left(a^2+b^2-p^2\right)=0x2+y2−3ax−4by+(a2+b2−p2)=0

  2. B

    2ax+2by−(a2−b2+p2)=02 a x+2 b y-\left(a^2-b^2+p^2\right)=02ax+2by−(a2−b2+p2)=0

  3. C

    x2+y2−2ax−3by+(a2−b2−p2)=0x^2+y^2-2 a x-3 b y+\left(a^2-b^2-p^2\right)=0x2+y2−2ax−3by+(a2−b2−p2)=0

  4. D

    2ax+2by−(a2+b2+p2)=02 a x+2 b y-\left(a^2+b^2+p^2\right)=02ax+2by−(a2+b2+p2)=0

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