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Locus of a centriod of the triangle whose vertices are (a cos t, a sin t),(b sin t,-b cos t) and (1,0), where t is a parameter, is

JEE Main 2003 — Mathematics Coordinate Geometry

2003mcqhard

Locus of a centriod of the triangle whose vertices are (acos⁡t,asin⁡t),(bsin⁡t,−bcos⁡t)(a \cos t, a \sin t),(b \sin t,-b \cos t)(acost,asint),(bsint,−bcost) and (1,0)(1,0)(1,0), where ttt is a parameter, is

Official previous-year question

Held on 30 Apr 2003 · Verified 6 Jul 2026.

Options

  1. A

    (3x+1)2+(3y)2=a2−b2(3 x+1)^2+(3 y)^2=a^2-b^2(3x+1)2+(3y)2=a2−b2

  2. B

    (3x−1)2+(3y)2=a2−b2(3 x-1)^2+(3 y)^2=a^2-b^2(3x−1)2+(3y)2=a2−b2

  3. C

    (3x−1)2+(3y)2=a2+b2(3 x-1)^2+(3 y)^2=a^2+b^2(3x−1)2+(3y)2=a2+b2

  4. D

    (3x+1)2+(3y)2=a2+b2(3 x+1)^2+(3 y)^2=a^2+b^2(3x+1)2+(3y)2=a2+b2

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