(h−a1)2+(k−b1)2=(h−a2)2+(k−b2)2 (a1−a2)x+(b1−b2)y+21(a22+b22−a12−b12)=0 C=21(a22+b22−a12−b12)
If the equation of the locus of a point equidistant from the point (a_1, b_1 ) and (a_2, b_2 ) is (a_1-b_2 ) x+ (a_1-b_2 ) y+c=0, then the value of…
JEE Main 2003 — Mathematics Coordinate Geometry
If the equation of the locus of a point equidistant from the point (a1,b1) and (a2,b2) is (a1−b2)x+(a1−b2)y+c=0, then the value of 'c' is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Options
- A
a12+b12−a22−b22
- B
21a22+b22−a12−b12
- C
a12−a22+b12−b22
- D
21(a12+a22+b12+b22)
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