Inorganic Chemistry PYQ — Page 49

In graphite and diamond, the percentage of $p$ characters of the hybrid orbitals in hybridization are respectively:

Identify the pair in which the geometry of the species is T-shaped and square-pyramidal, respectively,

The correct order of electron affinity is:

Identify the pair in which the geometry of the species is T-shape and square pyramidal, respectively

Which of the following conversions involves change in both shape and hybridisation?

The decreasing order of bond angles in $\mathrm{BF}_3, \mathrm{NH}_3, \mathrm{PF}_3$ and $\mathrm{I}_3^{-}$is :

The incorrect statement is:

Lithium aluminium hydride reacts with silicon tetrachloride to form:

In the molecular orbital diagram for the molecular ion, $\mathrm{N}_2^{+}$, the number of electrons in the $\sigma_{2 p}$ molecular orbital is :

Which of the following compounds contain(s) no covalent bond(s)? $\mathrm{KCl}, {\mathrm{PH}}_{3}, {O}_{2}, {B}_{2}{H}_{6}, {H}_{2}{\mathrm{SO}}_{4}$

Consider the following reaction and statements: ${[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Br}}_{2}]}^{+}+{\mathrm{Br}}^{-}\rightarrow [\mathrm{Co}{({\mathrm{NH}}_{3})}_{3}{\mathrm{Br}}_{3}]+{\mathrm{NH}}_{3}$ (i) Two isomers are produced if the reactant complex ion is a cis-isomer. (ii) Two isomers are produced if the reactant complex ion is a trans-isomer. (iii) Only one isomer is produced if the reactant complex ion is a trans-isomer. (iv) Only one isomer is produced if the reactant complex ion is a cis-isomer. The correct statements are

For $\mathrm{Na}^{+}, \mathrm{Mg}^{2+}, \mathrm{F}^{-}$and $\mathrm{O}^{2-}$; the correct order of increasing Ionic radii is :

Total number of lone pair of electrons in ${{I}_{3}}^{-}$ ion is:

The most polar compound among the following is:

When $X{O}_{2}$ is fused with an alkali metal hydroxide in presence of an oxidizing agent such as ${\mathrm{KNO}}_{3}$; a dark green product is formed which disproportionate in acidic solution to afford a dark purple solution. $X$ is:

The total number of possible isomers for squareplanar $\left[\mathrm{Pt}(\mathrm{Cl})\left(\mathrm{NO}_2\right)\left(\mathrm{NO}_3\right)(\mathrm{SCN})\right]^{2-}$ is:

Which of the following complexes will show geometrical isomerism?

For ${\mathrm{Na}}^{+}, {\mathrm{Mg}}^{2+}, {F}^{-}$ and ${O}^{2-}$, the correct order of increasing ionic radii is:

Among the oxides of nitrogen: ${N}_{2}{O}_{3}, {N}_{2}{O}_{4} and {N}_{2}{O}_{5};$ the molecule$(s)$ having nitrogen - nitrogen bond is/are:

The decreasing order of bond angles in${\mathrm{BF}}_{3}, {\mathrm{NH}}_{3},{\mathrm{PF}}_{3}$ and ${I}_{3}^{-}$ is:

A group 13 element ${ }^{'}{X}^{'}$ reacts with chlorine gas to produce a compound ${\mathrm{XCl}}_{3}. {\mathrm{XCl}}_{3}$ is electron deficient and easily reacts with ${\mathrm{NH}}_{3} \mathrm{to} \mathrm{form} {\mathrm{Cl}}_{3}X\leftarrow {\mathrm{NH}}_{3}$ adduct; however, ${\mathrm{XCl}}_{3}$ does not dimerize. X is:

The oxidation states of $\mathrm{Cr}$ in $[\mathrm{Cr}{({H}_{2}O)}_{6}]{\mathrm{Cl}}_{3}, [\mathrm{Cr}{({C}_{6}{H}_{6})}_{2}]$ and ${K}_{2}[\mathrm{Cr}{(\mathrm{CN})}_{2}{(O)}_{2}({O}_{2})({\mathrm{NH}}_{3})]$, respectively, are:

The correct combination is :

The number of $\mathrm{P}-\mathrm{O}$ bonds in $\mathrm{P}_4 \mathrm{O}_6$ is: