JEE Main Chemistry — Inorganic Chemistry previous year questions with solutions.
Iodine reacts with concentrated $HN{O}_{3}$ to yield $Y$ along with other products. The oxidation state of iodine in $Y$ , is:
Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of:
The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:
Thermal decomposition of a Mn compound $(X)$ at $513 K$ results in compound $Y,$ $Mn{O}_{2}$ and a gaseous product. $Mn{O}_{2}$ reacts with $NaCl$ and concentrated ${H}_{2}S{O}_{4}$ to give a pungent gas$Z$ . $X, Y$ and $Z,$ respectively, are:
Three complexes, ${[CoCl{(N{H}_{3})}_{5}]}^{2+}(I), {[Co{(N{H}_{3})}_{5}{H}_{2}O]}^{3+}(II)$ and ${[Co{(N{H}_{3})}_{6}]}^{3+}(III)$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is:
Among the following, the molecule expected to be stabilized by anion formation is: ${C}_{2}, {O}_{2}, NO, {F}_{2}$
The correct option with respect to the Pauling electronegativity values of the elements is:
The correct statement about $I{\mathrm{Cl}}_{5}$ and $I{\mathrm{Cl}}_{4}^{-}$ is:
The element having the greatest difference between its first and second ionization energies, is
The hydride that is NOT electron deficient is:
The oxoacid of sulphur that does not contain bond between sulphur atom is:
The pair that has similar atomic radii is:
The metal that gives hydrogen gas upon treatment with both the acid as well as the base is
The number of water molecules not coordinated to copper ion directly in $CuS{O}_{4}\cdot 5{H}_{2}O,$ is
Consider the hydrated ions of $T{i}^{2+}, {V}^{2+}, T{i}^{3+}$ and $S{c}^{3+}$ . The correct order of their spin-only magnetic moments is:
$\quad \mathrm{A} \stackrel{4 \mathrm{KOH}, \mathrm{O}_{2}}{\longrightarrow} \underset{(\mathrm{Green})}{2 \mathrm{~B}}+2 \mathrm{H}_{2} \mathrm{O}$ $\mathrm{B} \stackrel{4 \mathrm{HCl}}{\longrightarrow} \underset{(\text { Purple })}{2 \mathrm{C}}+\mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$ $2 \mathrm{C} \stackrel{\mathrm{H}_{2} \mathrm{O}, \mathrm{KI}}{\longrightarrow} 2 \mathrm{~A}+\mathrm{KOH}+\mathrm{D}$ In the above sequence of reactions, A and D, respectively, are:
The chloride that CANNOT get hydrolysed is:
The coordination numbers of $Co$ and $Al$ in $[Co(Cl){(en)}_{2}]Cl$ and ${K}_{3}[Al{({C}_{2}{O}_{4})}_{3}],$ respectively are: (en $=$ ethane-1, 2-diamine)
The incorrect statement is.
The crystal field stabilization energy (CFSE) of $[Fe{({H}_{2}O)}_{6}]C{l}_{2}$ and ${K}_{2}[NiC{l}_{4}]$, respectively, are:
The correct statements among I to III are: (I) Valence bond theory cannot explain the color exhibited by transition metal complexes. (II) Valence bond theory can predict quantitatively the magnetic properties of transition metal complexes. (III) Valence bond theory cannot distinguish ligands as weak and strong field ones.
The maximum possible denticities of a ligand given below towards a common transition and inner-transition metal ion, respectively, are: 
The complex that has highest crystal field splitting energy $(\Delta )$ , is:
The ion that has ${sp}^{3}{d}^{2}$ hybridization for the central atom is: