Inorganic Chemistry PYQ — Page 45

The species that can have a trans-isomer is: $(en = ethane-1, 2-diamine, ox=oxalate)$

The correct order of the oxidation states of nitrogen in $NO, {N}_{2}O, N{O}_{2}$ and ${N}_{2}{O}_{3}$ is

The statement that is INCORRECT about the interstitial compounds is:

Chlorine on reaction with hot and concentrated sodium hydroxide gives.

The number of pentagons in ${C}_{60}$ and trigons (triangles) in white phosphorus, are;

The transition elements that has the lowest enthalpy of atomisation is:

The correct statement among the following is:

$\quad \mathrm{A} \stackrel{4 \mathrm{KOH}, \mathrm{O}_{2}}{\longrightarrow} \underset{(\mathrm{Green})}{2 \mathrm{~B}}+2 \mathrm{H}_{2} \mathrm{O}$ $\mathrm{B} \stackrel{4 \mathrm{HCl}}{\longrightarrow} \underset{(\text { Purple })}{2 \mathrm{C}}+\mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$ $2 \mathrm{C} \stackrel{\mathrm{H}_{2} \mathrm{O}, \mathrm{KI}}{\longrightarrow} 2 \mathrm{~A}+\mathrm{KOH}+\mathrm{D}$ In the above sequence of reactions, A and D, respectively, are:

Homoleptic octahedral complexes of a metal ion $'{M}^{3+}'$ with three monodentate ligands ${L}_{1},{L}_{2}and {L}_{3}$ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is:

The coordination number of Th in $\mathrm{K}_{4}\left[\mathrm{Th}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]$ is: $\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}=\right.$ oxalato $)$

The correct order of catenation is:

The effect of lanthanoid contraction in the lanthanoid series of elements by and large means

The highest possible oxidation states of uranium and plutonium, respectively, are

$M{n}_{2}{(CO)}_{10}$ is an organometallic compound due to the presence of:

The metal's $d-$ orbitals that are directly facing the ligands in ${K}_{3}[Co{(CN)}_{6}]$ are:

The element that shows greater ability to form $p\pi -p\pi$ multiple bonds is:

Iodine reacts with concentrated $HN{O}_{3}$ to yield $Y$ along with other products. The oxidation state of iodine in $Y$ , is:

Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of:

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:

Thermal decomposition of a Mn compound $(X)$ at $513 K$ results in compound $Y,$ $Mn{O}_{2}$ and a gaseous product. $Mn{O}_{2}$ reacts with $NaCl$ and concentrated ${H}_{2}S{O}_{4}$ to give a pungent gas$Z$ . $X, Y$ and $Z,$ respectively, are:

The pair that has similar atomic radii is:

The correct option with respect to the Pauling electronegativity values of the elements is:

The correct statement about $I{\mathrm{Cl}}_{5}$ and $I{\mathrm{Cl}}_{4}^{-}$ is:

The element having the greatest difference between its first and second ionization energies, is