Let X be random variable which assumes x_1, x_2, x_3, x_4 such that 2P(X=x_1)= 3P(X=x_2)=P(X=x_3)=5P(X=x_4) , then the probability distribution of X…

If f(x) = 2x + 3, then f⁻¹(x) is:

A relation R in the set A = {1, 2,3, 4} is given by R = {(1,1), (2,2), (1,2), (2,3), (3,4), (4,4), (1,3), (2,4), (1,4)} is

If $P(A) = \frac{3}{5}$, $P(B) = \frac{1}{2}$ and $P(A \cap B) = \frac{1}{4}$, then $P(\overline{A} | \overline{B})$ is

The maximum value of a LPP $z = 3x + 4y$ subject to the constraints: $x + y \leq 6$, $x \geq 0$, $y \geq 0$ is:

Match List-I with List-II | List-I | List-II | |---|---| | (A) The number of possible matrices of order 3x3 with each entry 1 or 0 | (I) $2^4$ | | (B) The number of possible matrices of order 2x3 with each entry 1 or 0 | (II) $2^9$ | | (C) The number of possible matrices of order 2x3 with each entry 0,1,2 | (III) $2^6$ | | (D) The number of possible matrices of order 2x2 with each entry 1 or 0 | (IV) $3^6$ | Choose the correct answer from the options given below: