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Let A = [a_ij] is given by A = …. Then the matrix B = [b_ij], where b_ij = Minor of a_ij is:

CUET UG 2025 — Mathematics Algebra

2025mcqmedium

Let A=[aij]A = [a_{ij}]A=[aij​] is given by A=[1−1234−52−13]A = \begin{bmatrix} 1 & -1 & 2 \\ 3 & 4 & -5 \\ 2 & -1 & 3 \end{bmatrix}A=​132​−14−1​2−53​​. Then the matrix B=[bij]B = [b_{ij}]B=[bij​], where bijb_{ij}bij​ = Minor of aija_{ij}aij​ is:

Official previous-year question

Held on 27 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    [719−11−1−11−3−117]\begin{bmatrix} 7 & 19 & -11 \\ -1 & -1 & 1 \\ -3 & -11 & 7 \end{bmatrix}​7−1−3​19−1−11​−1117​​

  2. B

    [7−19115−1−12117]\begin{bmatrix} 7 & -19 & 11 \\ 5 & -1 & -1 \\ 2 & 11 & 7 \end{bmatrix}​752​−19−111​11−17​​

  3. C

    [7−5−3191−11−1117]\begin{bmatrix} 7 & -5 & -3 \\ 19 & 1 & -11 \\ -11 & 1 & 7 \end{bmatrix}​719−11​−511​−3−117​​

  4. D

    [719−11−3117−2−1−1]\begin{bmatrix} 7 & 19 & -11 \\ -3 & 11 & 7 \\ -2 & -1 & -1 \end{bmatrix}​7−3−2​1911−1​−117−1​​

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