Given ∣a∣=2, ∣b∣=3, and a⋅b=4
For any two vectors, the magnitude of their difference is:
∣a−b∣2=∣a∣2+∣b∣2−2(a⋅b)
Substituting the given values:
∣a−b∣2=(2)2+(3)2−2(4)
∣a−b∣2=4+9−8
∣a−b∣2=5
Taking the square root:
∣a−b∣=5
Therefore, ∣a−b∣=5
CUET UG 2025 — Mathematics Algebra
Let a,b be two vectors such that ∣a∣=2,∣b∣=3,a⋅b=4, then ∣a−b∣ is equal to
Held on 13 May 2025 · Verified 13 Jul 2026.
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