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Three defective bulbs are mixed with 8 good ones. If three bulbs are drawn one by one with replacement, the probabilities of getting exactly 1…

CUET UG 2024 — Mathematics Algebra

2024mcqhard

Three defective bulbs are mixed with 888 good ones. If three bulbs are drawn one by one with replacement, the probabilities of getting exactly 111 defective, more than 222 defective, no defective and more than 111 defective respectively are:

Official previous-year question

Held on 16 May 2024 · Verified 13 Jul 2026.

Options

  1. A

    271331,5761331,2431331\frac{27}{1331}, \frac{576}{1331}, \frac{243}{1331}133127​,1331576​,1331243​ and 5121331\frac{512}{1331}1331512​

  2. B

    271331,2431331,5761331\frac{27}{1331}, \frac{243}{1331}, \frac{576}{1331}133127​,1331243​,1331576​ and 5121331\frac{512}{1331}1331512​

  3. C

    5761331,271331,5121331\frac{576}{1331}, \frac{27}{1331}, \frac{512}{1331}1331576​,133127​,1331512​ and 2431331\frac{243}{1331}1331243​

  4. D

    2431331,5761331,5121331\frac{243}{1331}, \frac{576}{1331}, \frac{512}{1331}1331243​,1331576​,1331512​ and 271331\frac{27}{1331}133127​

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