Case 1: Red drawn from Urn I (prob 6/10), then Urn II has 5R, 6B; P(red)=5/11.
Case 2: Black drawn (prob 4/10), Urn II has 4R, 7B; P(red)=4/11.
Total =106⋅115+104⋅114=11046=5523.
Urn I contains 6 red balls and 4 black balls and Urn II contains 4 red balls and 6 black balls. One ball is drawn at random from Urn I and placed in…
CUET UG 2023 — Mathematics Algebra
2023mcqmedium
Urn I contains 6 red balls and 4 black balls and Urn II contains 4 red balls and 6 black balls. One ball is drawn at random from Urn I and placed in Urn II. If one ball is drawn at random from Urn II, then the probability that it is a red ball is :
Official previous-year question
Held on 22 May 2023 · Verified 13 Jul 2026.
Options
- A
53
- B
114
- C
5523
- D
52
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