(A) ∣AT∣=∣A∣, IV.
(B) A(adjA)=(adjA)A=∣A∣I, III.
(C) A−1∣A∣=∣A∣adjA⋅∣A∣=adjA, II.
(D) (AB)−1=B−1A−1, I.

Choose the correct answer from the options given below
Held on 22 May 2023 · Verified 13 Jul 2026.
(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
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