a=i^−j^, b=j^−k^. a⋅b=(1)(0)+(−1)(1)+(0)(−1)=−1. ∣a∣=2, ∣b∣=2. cosθ=2⋅2−1=−21. So θ=2π/3.
The angle between the vectors i^−j^ and j^−k^ is:
Held on 10 Aug 2022 · Verified 13 Jul 2026.
65π
3−π
32π
3π
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