(A) Independent: P(E′∩F′)=[1−P(E)][1−P(F)] which is (IV). (B) P(E′/F)=1−P(E/F) which is (I). (C) Independent: P(E∩F′)=P(E)P(F′) which is (III). (D) P(E/F)=P(F/E) implies P(E)=P(F) which is (II).
CUET UG 2022 — Mathematics Algebra
Match List - I with List - II.
| List - I | List - II |
|---|---|
| (A) Two events E and F will be independent if P(E′F′) is equal to | (I) 1−P(E/F) |
| (B) If P(F)=0, then P(E′/F) is equal to | (II) P(E)=P(F) |
| (C) If E and F are independent events, then | (III) P(E∩F′)=P(E)⋅P(F′) |
| (D) If P(E∩F)=0 and P(E/F)=P(F/E), then | (IV) [1−P(E)][1−P(F)] |
Choose the correct answer from the options given below :
Held on 17 Aug 2022 · Verified 13 Jul 2026.
(A) - (IV), (B) - (I), (C) - (II), (D) - (III)
(A) - (II), (B) - (IV), (C) - (III), (D) - (I)
(A) - (II), (B) - (III), (C) - (IV), (D) - (I)
(A) - (IV), (B) - (I), (C) - (III), (D) - (II)
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