∣OA∣=4+1+1=6 (A is false).
∣OB∣=3 (B true).
AB=OB−OA=−i^+2j^−2k^ (C true).
OA⋅OB=2−1−1=0 (D true).
Since dot product is zero, vectors are perpendicular not parallel (E false).
Let OA = 2 i - j + k and OB = i + j - k. Then A. The magnitude of vector OA is 6 B. The magnitude of vector OB is √3 C. The vector AB is (- i + 2 j -…
CUET UG 2022 — Mathematics Algebra
2022mcqmedium
Let OA=2i^−j^+k^ and OB=i^+j^−k^. Then
A. The magnitude of vector OA is 6
B. The magnitude of vector OB is 3
C. The vector AB is (−i^+2j^−2k^)
D. OA⋅OB=0
E. OA∥OB
Choose the correct answer from the options given below:
Official previous-year question
Held on 6 Aug 2022 · Verified 13 Jul 2026.
Options
- A
A, B, C, D Only
- B
A, B, E Only
- C
C, D, E Only
- D
B, C, D Only
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