Compute ∣A∣=1(1−8)−2(2−12)+3(4−3)=−7+20+3=16. Since A⋅adj(A)=∣A∣I, we have (adjA)−1=∣A∣A=161A.
If A = …, then which of the following is the value of ( adj A)^-1
CUET UG 2022 — Mathematics Algebra
2022mcqmedium
If A=123212341, then which of the following is the value of (adj A)−1
Official previous-year question
Held on 16 Jul 2022 · Verified 13 Jul 2026.
Options
- A
123214321
- B
11/21/31/211/41/31/21
- C
161123212341
- D
−241123214321
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