2[abdc]+3[10−12]=[9121518]
So [2a+32b2d−32c+6]=[9121518].
This gives a=3, d=9, b=6, c=6. Then ∣a+b−c−d∣=∣3+6−6−9∣=6.
If 2[abdc]+3[10−12]=3[3456], then the value of ∣a+b−c−d∣ is
Held on 30 Aug 2022 · Verified 13 Jul 2026.
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