Let Q be of order p×q, so QT is q×p. For PQT computable: columns of P = rows of QT, so n=q. For QTP computable: columns of QT = rows of P, so p=m. Hence Q is m×n.
If P is matrix of order m × n and Q is a matrix such that PQ' and Q'P are both computable, then the order of matrix Q is
CUET UG 2022 — Mathematics Algebra
2022mcqmedium
If P is matrix of order m×n and Q is a matrix such that PQ' and Q'P are both computable, then the order of matrix Q is
Official previous-year question
Held on 16 Jul 2022 · Verified 13 Jul 2026.
Options
- A
m×n
- B
n×m
- C
n×n
- D
m×m
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