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If a = a_1 i + a_2 j + a_3 k and b = b_1 i + b_2 j + b_3 k are two non zero vectors inclined at an angle θ, then identify the correct option out of…

CUET UG 2022 — Mathematics Algebra

2022mcqmedium

If a⃗=a1i^+a2j^+a3k^\vec{a} = a_1\hat{i} + a_2\hat{j} + a_3\hat{k}a=a1​i^+a2​j^​+a3​k^ and b⃗=b1i^+b2j^+b3k^\vec{b} = b_1\hat{i} + b_2\hat{j} + b_3\hat{k}b=b1​i^+b2​j^​+b3​k^ are two non zero vectors inclined at an angle θ\thetaθ, then identify the correct option out of the given options.
(a) cos⁡θ=a⃗⋅b⃗∣a⃗∣⋅∣b⃗∣\cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}| \cdot |\vec{b}|}cosθ=∣a∣⋅∣b∣a⋅b​
(b) a⃗\vec{a}a and b⃗\vec{b}b are perpendicular, if a1b1+a2b2+a3b3=0a_1 b_1 + a_2 b_2 + a_3 b_3 = 0a1​b1​+a2​b2​+a3​b3​=0
(c) a⃗\vec{a}a and b⃗\vec{b}b are perpendicular, if a1b1=a2b2≠c1c2\frac{a_1}{b_1} = \frac{a_2}{b_2} \neq \frac{c_1}{c_2}b1​a1​​=b2​a2​​=c2​c1​​
(d) for θ=π\theta = \piθ=π, a⃗×b⃗=0\vec{a} \times \vec{b} = 0a×b=0
(e) cos⁡θ=∣a⃗×b⃗∣∣a⃗∣⋅∣b⃗∣\cos\theta = \frac{|\vec{a} \times \vec{b}|}{|\vec{a}| \cdot |\vec{b}|}cosθ=∣a∣⋅∣b∣∣a×b∣​
Choose the most appropriate answer from the options given below

Official previous-year question

Held on 30 Aug 2022 · Verified 13 Jul 2026.

Options

  1. A

    (a), (b) and (d) only

  2. B

    (a), (b) and (e) only

  3. C

    (b), (d) and (e) only

  4. D

    (a) and (b) only

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