Inorganic Chemistry PYQ — Page 3

Select the element $(M)$ whose trihalides cannot be hydrolysed to produce an ion of the form $\left[\mathrm{M}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$

Which one of the following statements is incorrect related to Molecular Orbital Theory?

Which amongst the following compounds will show geometrical isomerism?

Type of isomerism exhibited by compounds $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3,\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}^{\mathrm{Cl}} \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}_2 . \mathrm{H}_2 \mathrm{O}\right.$ and the value of coordination number $(\mathrm{CN})$ of central metal ion in all these compounds, respectively is:

Homoleptic complex from the following complexes is:

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R: Assertion A: Metallic sodium dissolves in liquid ammonia giving a deep blue solution, which is paramagnetic. Reasons R: The deep blue solution is due to the formation of amide. In the light of the above statements, choose the correct answer from the options given below:

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Ionisation enthalpies of early actinoids are lower than for early lanthanoids. Reason (R) : Electrons are entering $5 f$ orbitals in actinoids which experience greater shielding from nuclear charge. In the light of the above statements, choose the correct answer from the options given below:

Which complex compound is most stable?

Which of the following statements are INCORRECT? A. All the transition metals except scandium form $\mathrm{MO}$ oxides which are ionic. B. The highest oxidation number corresponding to the group number in transition metal oxides is attained in ${\mathrm{Sc}}_{2}{O}_{3}$ to ${\mathrm{Mn}}_{2}{O}_{7}$ . C. Basic character increases from ${V}_{2}{O}_{3}\mathrm{to}{V}_{2}{O}_{4}\mathrm{to}{V}_{2}{O}_{5}$. D. ${V}_{2}{O}_{4}$ dissolves in acids to give ${\mathrm{VO}}_{4}^{-3}$ salts. E. $\mathrm{CrO}$ is basic but ${\mathrm{Cr}}_{2}{O}_{3}$ is amphoteric. Choose the correct answer from the options given below:

The correct sequence given below containing neutral, acidic, basic and amphoteric oxide each, respectively, is

The number of $\sigma$ bonds, $\pi$ bonds and lone pair of electrons in pyridine, respectively.

Which of the following forms a set of a complex and a double salt, respectively?

The correct order of energies of molecular orbitals of ${N}_{2}$ molecule, is:

The correct order of dipole moments for molecules $\mathrm{NH}_3, \mathrm{H}_2 \mathrm{~S}, \mathrm{CH}_4$ and $\mathrm{HF}$, is

Amongst the following, the total number of species NOT having eight electrons around central atom in its outer most shell, is ${\mathrm{NH}}_{3},{\mathrm{AlCl}}_{3},{\mathrm{BeCl}}_{2},{\mathrm{CCl}}_{4},{\mathrm{PCl}}_{5}$

Match List-I with List-II <table class="pyq-table"><tbody><tr><td colspan="2" rowspan="1">List-I(Oxo acids of Sulphur)</td><td colspan="2" rowspan="1">List-II(Bonds)</td></tr><tr><td>A</td><td>Peroxodisulphuric acid</td><td>$I$</td><td>Two S-OH, Four S=O, One S-O-S</td></tr><tr><td>B</td><td>Sulphuric acid</td><td>$\mathrm{II}$</td><td>Two S-OH, One S=O</td></tr><tr><td>C</td><td>Pyrosulphuric acid</td><td>$\mathrm{III}$</td><td>Two S-OH, Four S=O, One S-O-O-S</td></tr><tr><td>D</td><td>Sulphurous acid</td><td>$\mathrm{IV}$</td><td>Two S-OH, Two S=O</td></tr></tbody></table>

Intermolecular forces are forces of attraction and repulsion between interacting particles that will include : A. dipole-dipole forces. B. dipole-induced dipole forces. C. hydrogen bonding. D. covalent bonding. E. dispersion forces. Choose the most appropriate answer from the options given below:

Taking stability as the factor, which one of the following represent the correct relationship?

Match list-I with List-II : <table class="pyq-table"><tbody><tr><td>List - I</td><td>List - II</td></tr><tr><td>A. Coke</td><td>I. Carbon atoms are ${\mathrm{sp}}^{3}$ hybridised</td></tr><tr><td>B. Diamond</td><td>II. Used as dry lubricants</td></tr><tr><td>C. Fullerene</td><td>III. Used as a reducing agent</td></tr><tr><td>D. Graphite</td><td>IV. Cage like molecules</td></tr></tbody></table>Choose the correct answer from the options given below:

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Ionisation enthalpy increases along each series of the transition elements from left to right. However, small variations occur. Reason (R) : There is corresponding increase in nuclear charge which accompanies the filling of electrons in the inner dorbitals. In the light of the above statements, choose the most appropriate answer from the options given below.

Which of the following is correctly matched?

The element with highest electronegativity is

$\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \stackrel{\text { heat }}{\longrightarrow} \mathrm{X}+\mathrm{NaBO}_2$ in the above reaction the product " $\mathrm{X}$ " is :

In the neutral or faintly alkaline medium, ${\mathrm{KMnO}}_{4}$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from