Using the Napier's analogy and cosine rule:
$\cos(A-B) = \frac{31}{32}$, $a = 5$, $b = 4$
After applying the formula and solving: $c = 6$
Verified 30 May 2026.
In triangle $ABC$, if $a = 5$, $b = 4$, and $\cos(A - B) = \frac{31}{32}$, then $c$ is:
$6$
$7$
$8$
$5$
Using the Napier's analogy and cosine rule:
$\cos(A-B) = \frac{31}{32}$, $a = 5$, $b = 4$
After applying the formula and solving: $c = 6$
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