Let α=sin−1(132).
Then sinα=132, cosα=133, tanα=32. So tan(2α)=1−942⋅32=512.
Let γ=cos−1(103).
Then cosγ=103, sinγ=101, tanγ=31. So tan(2γ)=1−912⋅31=43.
Therefore tan(2α−2γ)=1+512⋅43512−43=20562033=5633
Considering the principal values of inverse trigonometric functions, the value of the expression tan(2sin−1(132)−2cos−1(103)) is equal to :
Held on 28 Jan 2026 · Verified 6 Jul 2026.
6316
−5633
−6316
5633
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