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If cos ^2 48°-sin ^2 12° sin ^2 24°-sin ^2 6°= α+β √5 2, where α, β ∈ mathbbN, then α+β is equal to _____

JEE Main 2026 — Mathematics Trigonometry

2026integermedium

If cos⁡248∘−sin⁡212∘sin⁡224∘−sin⁡26∘=α+β52\frac{\cos ^{2} 48^{\circ}-\sin ^{2} 12^{\circ}}{\sin ^{2} 24^{\circ}-\sin ^{2} 6^{\circ}}=\frac{\alpha+\beta \sqrt{5}}{2}sin224∘−sin26∘cos248∘−sin212∘​=2α+β5​​, where α,β∈N\alpha, \beta \in \mathbb{N}α,β∈N, then α+β\alpha+\betaα+β is equal to _____\_\_\_\_\______

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Held on 22 Jan 2026 · Verified 6 Jul 2026.

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