In the third quadrant, both $\sin\theta$ and $\cos\theta$ are negative.
$\tan\theta = \frac{3}{4}$, hypotenuse $= \sqrt{9+16} = 5$
$$\sin\theta = -\frac{3}{5}$$
Verified 30 May 2026.
If $\tan\theta = \frac{3}{4}$ and $\theta$ is in the third quadrant, then $\sin\theta$ is:
$-\frac{3}{5}$
$\frac{3}{5}$
$-\frac{4}{5}$
$\frac{4}{5}$
In the third quadrant, both $\sin\theta$ and $\cos\theta$ are negative.
$\tan\theta = \frac{3}{4}$, hypotenuse $= \sqrt{9+16} = 5$
$$\sin\theta = -\frac{3}{5}$$
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